(x^2)(y^2)+(x)(y)=2

Solution for (x^2)(y^2)+(x)(y)=2 equation:

Simplifying
(x2)(y2) + (x)(y) = 2

Multiply x2 * y2
x2y2 + (x)(y) = 2

Multiply x * y
x2y2 + xy = 2

Reorder the terms:
xy + x2y2 = 2

Solving
xy + x2y2 = 2

Solving for variable 'x'.

Reorder the terms:
-2 + xy + x2y2 = 2 + -2

Combine like terms: 2 + -2 = 0
-2 + xy + x2y2 = 0

Factor a trinomial.
(-2 + -1xy)(1 + -1xy) = 0

Subproblem 1
Set the factor '(-2 + -1xy)' equal to zero and attempt to solve:

Simplifying
-2 + -1xy = 0

Solving
-2 + -1xy = 0

Move all terms containing x to the left, all other terms to the right.

Add '2' to each side of the equation.
-2 + 2 + -1xy = 0 + 2

Combine like terms: -2 + 2 = 0
0 + -1xy = 0 + 2
-1xy = 0 + 2

Combine like terms: 0 + 2 = 2
-1xy = 2

Divide each side by '-1y'.
x = -2y-1

Simplifying
x = -2y-1
Subproblem 2
Set the factor '(1 + -1xy)' equal to zero and attempt to solve:

Simplifying
1 + -1xy = 0

Solving
1 + -1xy = 0

Move all terms containing x to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + -1xy = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -1xy = 0 + -1
-1xy = 0 + -1

Combine like terms: 0 + -1 = -1
-1xy = -1

Divide each side by '-1y'.
x = y-1

Simplifying
x = y-1
Solution
x = {-2y-1, y-1}